hey guys plz help me in this question with full explanation
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Given:- BE and CF are bisectors of angle ABC and angle ACD
TO PROVE:-<BEC=1/2<BAC
PROOF:- <ACD=<ABC+<BAC[Sun of two opposite interior angles of a triangle is equal to its exterior angle]
=> 1/2<ACD=1/2(<ABC+<BAC)
=> <ECD=1/2(<ABC+<BAC) ............ (1)
SINCE, <ECD is the exterior angle of triangle EBC
=> <ECD= <ECB+<EBC[Sum of two opposite side of a triangle is equal to its exterior angle]
=> <ECD=1/2(<ABC+<BEC) ............. (2)
From (1) &(2) we get,
1/2<ABC+1/2<BAC=1/2<ABC+1/2 <BEC
= <BEC=1/2 <BAC
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