Question

Hey Guys, Plz help me out...

Find all the zeroes of polynomial 8x⁴+8x³+-18x²-20x-5

if two zeroes are √5/2 and (-√5/2)​

Answer 1

Answer:

l think this is your answer ☝️☝️

Answer 2

Other zeroes = . 1/2 of

polynomial 8x4 + 8x3 - 18x2

- 20x - 5 if two of its zeroes

arev(5/2) and - V(5/2)

Step-by-step explanation:

8x4 + 8x3 - 18x2 - 20x-5

two of its zeroes are v(5/2) and - V(5/2)

(x - V(5/2))(x + V(5/2))

= x2 - 5/2

= (2x - 5)/2

=> (2x2 - 5 ) is one of the factor

2

8x4 + 8x3 - 18x2 - 20x-5

= (2x2 - 5) (4x2 + 4x + 1)

4x2 + 4x + 1

= 4x2 + 2x + 2x + 1

=

=

+

= 2x(2x + 1) + 1(2x + 1)

= (2x + 1)(2x + 1)

+

Other zeroes = . 1/2