Question

hey guys plz help me with this q​

Answer 1

Konnichiwa

Ur answer is in the attachment (I have written it in black pen)

if u are a 12 th student just ping me I can clear ur doubts

thank and follow meh :)

Answer 2

◆【Solution】◆

You get your answer before so I am here to add some spice over it.

● What is electrode potential [E°] ?

In any type of cell there is couple of electrode dipped in the electrolyte Solution which contain Lot of electron which convey electric current. So to move electron we need a force called Electromotive Force which is cause due to potential difference between both electrode namely Electrode Potential.

● We can't add two Electrode potential.

But in order to find the electrode potential of any reaction (Combination of two reaction) But we can still find the answer through Gibbs free energy.

G = -nFE

where n is the transfer of electron in the given rexn

F is faraday Constant

E is electrode potential

I just skip the Derivation Final result is

n(3).E(3) = E(1).n(1) + E(2).n(2)

n(1) , E(1) is used for 1st rexn

n(3) , E(3) is used for resultant rexn

In your question.....

n(1) = n(2) = n(3) = 2

E(1) = 0.76

E(2) = -(0.41).....Coz we need reverse rexn

E(3) = 0.76 - 0.41

◆【0.35】◆

Thanks for following

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