Math, asked by brajeshraja, 1 year ago

Hey guys plz solve this ...


Aakash, Brajesh, and Sorav have a total of $93 in their wallets. Donna has $7 more than Chris. Austin has 3 times what Donna has. How much do they have in their wallets?

Answers

Answered by adityaK2517
2

Let the amount in Chris’s wallet be $x

Donna has $7 more than Chrish's wallet = $(x + 7)

Austin has 3 times than Donna's wallet = $3(x + 7)

According to the problem, Donna, chris, and Austin have a total of $93 in their wallets.

Therefore,

x + (x + 7) + 3(x + 7) = 93

x + x + 7 + 3x + 21 = 93

5x + 28 = 93

- 28 -28 (subtract 28 from both sides)

5x = 65

or, 5x/5 = 65/5 (Divide both sides by 5)

x = 13

Amount in Chris wallet = $x = $13

Amount in Donna's wallet = $(x + 7) = $(13 + 7) = $20

Amount in Austin 's wallet = $3(x + 7) = $3(13 + 7) = $3(20) = $ 60

Answer: Amount in Chris’s wallet: $13 ✔️

Amount in Donna's wallet: $20✔️

Amount in Austin's wallet: $60✔️

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Answered by 2Ritz6
6

Be happy....

\huge{Ritz\:Here}

Que ;-➡️. Aakash, Brajesh, and Sorav have a total of $93 in their wallets. Donna has $7 more than Chris. Austin has 3 times what Donna has. How much do they have in their wallets?⬅️

Solution:

\huge{Answer}

Let the amount in Chris’s wallet be $x

Donna has $7 more than Chrish's wallet = $(x + 7)

Austin has 3 times than Donna's wallet = $3(x + 7)

According to the problem, Donna, chris, and Austin have a total of $93 in their wallets.

Therefore,

x + (x + 7) + 3(x + 7) = 93

x + x + 7 + 3x + 21 = 93

  5x + 28 = 93

                   (subtract 28 from both sides)

________________

        5x     = 65

or, 5x/5 = 65/5    (Divide both sides by 5)

x = 13

Amount in Brajesh wallet = $x = $13

Amount in akash's wallet = $(x + 7) = $(13 + 7) = $20

Amount in sourav  's wallet = $3(x + 7) = $3(13 + 7) = $3(20) = $ 60

Answer: Amount in Brajesh’s wallet: $13

             Amount in aakash's wallet: $20

             Amount in  Sourav's wallet: $60

Hope it's help u ❤️❤️


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