hey guys plz solve this question
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hey mate ✌❤
here's ur answer ✍✍✍✍✍
____________________________
angle ade = angle aed { angle opp to equal sides are equal
=> angle adb = 180-ade { linear pair }
// ly angle aec = 180-aed ( same reason )
as angle ade = aed
=> angle adb = aec
Now in ∆ adb & ∆ aec
bd = dc { given }
ad = ae { given }
adb = aec { proved above }
Hence ∆ adb ≈ ∆ aec
By CPCT ab = ac
____________________________
⭐ hope it helps ⭐
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here's ur answer ✍✍✍✍✍
____________________________
angle ade = angle aed { angle opp to equal sides are equal
=> angle adb = 180-ade { linear pair }
// ly angle aec = 180-aed ( same reason )
as angle ade = aed
=> angle adb = aec
Now in ∆ adb & ∆ aec
bd = dc { given }
ad = ae { given }
adb = aec { proved above }
Hence ∆ adb ≈ ∆ aec
By CPCT ab = ac
____________________________
⭐ hope it helps ⭐
✔ Mark as brainliest ✔
❇⚛follow me⚛❇
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