Question

Hey guys,
Plz solve this question if you know the answer then only answer it otherwise leave it plz.

Answer 1

rn=0.529(n2/Z)A˙rn=0.529(n2/Z)A˙

vn=2.186×106(Z/n)m/svn=2.186×106(Z/n)m/s

T=2πr/v T=2πr/v

Substituting the values,Substituting the values,

T=1.5211×10−16(n3Z/2)s T=1.5211×10−16n3Z2s

ν=1/T ν=1T

ν=6.57×1015Z2n3 ν=6.57×1015Z2n3

For H-atom, Z=1For H-atom, Z=1

Since, the electron is in second orbit, n=2Since, the electron is in second orbit, n=2

Therefore,ν=6.57×1015×1223=8.217×1014HzTherefore,ν=6.57×1015×1223=8.217×1014Hzh