Question

hey guys......
plz ......tell me the solution of question no. 10 and 11.......plz ....urgently.....plz plz plz

Answer 1

10)ans:Steps:-
1)Draw triangle PQR ,QR=10.5 ,ang.Q=45,R=120
2)Bisect Q,R to intersect at a point A
3)Construct AB parallel to the arm of angle not meeting with B(PQ)
4)Similarly draw AC parallel to PR
5)Then triangle ABC is the required triangle.
Proof:
AB parallel PQ
So angleABC=anglePQR=45
Similarly for angleACB=angPRQ.=120

And angle PQA=angBAQ=angAQB(parallel)
So QB=AB
Similarly CR=AC
So,QR=10.5
=QB+BC+CR=10.5
=AB+BC+CA=10.5
Proved
Thanks for asking!

Answer 2

I was busy that's why I can't draw ,thank u