Question

hey guys!!!
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plzz help me to do this question
plzz.
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Answer 1

$\huge\mathfrak\red{Answer:-}$$<b>$
Avg. atomic mass of bromine

(79×49.7%)+(81×50.3%)
= 79×49.7/100 + 81×50.3/100
= 79×0.497 + 81×0.503
= 39.263 + 40.743
= 80.006u

So, the avg. mass of the bromine atom is 80.006u.

HOPE IT HELPS!!

Answer 2

Average atomic mass = total mass of mixture divide by total no. of moles