Question

Hey guys plzz help me to solve ques 8 ..... i am getting wrong answer....

Answer 1

HELLO DEAR
$\frac{6}{x} - \frac{2}{x - 1} = \frac{1}{x - 2} \\ = > \frac{6(x - 1) - 2x}{x(x - 1)} = \frac{1}{x - 2} \\ = > \frac{6x - 2x - 6}{( { x}^{2} - x)} = \frac{1}{x - 2} \\ = > \frac{(4x - 6)(x - 2)}{( {x}^{2} - x) } = 1 \\ = > 4 {x}^{2} - 8x - 6x + 12 = {x}^{2} - x \\ = > 4 {x}^{2} - {x}^{2} - 14x + x + 12 = 0 \\ = > 3 {x}^{2} - 13x + 12 = 0 \\ = > 3 {x}^{2} - 9x - 4x + 12 = 0 \\ = > 3x(x - 3) - 4(x - 3) = 0 \\ = > (3x - 4)(x - 3) = 0 \\ = > x = \frac{4}{3} \\ and \\ x = 3$
I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Hello everyone...

Here is the answer...

Hope this helps you...