Question

hey guys plzz solve this..... ​

Answer 1

Answer:

GIVEN THAT -

$\tan( \frac{a + b}{2} ) = \cot( \frac{c}{2} )$

$we \: \: know \: \: that \: \: -$

$\cot( a ) = \tan( {90}^{0} - a)$

So,

$\tan( \frac{a + b}{2} ) = \tan( \frac{\pi}{2} - \frac{c}{2} )$

$\frac{a + b}{2} = \frac{\pi}{2} - \frac{c}{2}$

$\frac{a + b + c}{2} = \frac{\pi}{2}$

$a + b + c = \pi$

So , it's a triangle.

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