hey guys plzz tell me this ques
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Heya user ,
Here is your answer !!
The possible outcomes in a single throw of a die are 1 , 2 , 3 , 4 , 5 and 6.
(1) probability that it will be an even number
= 2 , 4 , 6 .
P = 3 / 6 = 1/2
(2) probability that it will be an odd number
= 1 , 3 , 5
P = 3 / 6 = 1/2 .
(3) probability that it will not be an even number
= 1 , 3 , 5
P = 3 / 6 = 1/2 .
Hope it helps !!
Here is your answer !!
The possible outcomes in a single throw of a die are 1 , 2 , 3 , 4 , 5 and 6.
(1) probability that it will be an even number
= 2 , 4 , 6 .
P = 3 / 6 = 1/2
(2) probability that it will be an odd number
= 1 , 3 , 5
P = 3 / 6 = 1/2 .
(3) probability that it will not be an even number
= 1 , 3 , 5
P = 3 / 6 = 1/2 .
Hope it helps !!
dollysingh085pf3vtz:
tysm for ur wonderful answer
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