Question

Hey Guys plzzz answer this ......


find the area of the segment of a circle of radius 14 cm when the angle of the corresponding sector is 30 degree..

Answer 1

HELLO DEAR,

$area \: of \: segment = \frac{theta}{360} \times \pi {r}^{2} - \frac{1}{2} \times {r}^{2} sin \: theta \\ = > \frac{30}{360} \times \frac{22}{7} \times 14 \times 14 - \frac{1}{2} \times 14 \times 14 \sin(30) \\ = > 196( \frac{1}{12} \times \frac{22}{7} - \frac{1}{2} \times \frac{1}{2} ) \\ = > 196( \frac{11}{42} - \frac{1}{4} ) \\ = > 196( \frac{22 - 21}{84} ) \\ = > \frac{196}{84} \\ = > 2.33cm^{2}$
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Answer 2

Dear Student ,

Please find below the solution to the asked query :

Area of segment=θ360×πr2−12r2 sin θ=30360×227×14×14−12×14×14×sin 30=196 (112×227−12×12)=196 (1142−14)=196 (22−2184)=19684=2.33 cm2 .   ANS...