Question

HEY GUYS⭐⭐
PLZZZ HELP IN MY Q'S
CLASS 11
ITS VERY URGENT
I'LL MARK AS BRAINLIEST ☺️☺️NO SPAMMING ⭕⭕
EXPLAIN PROPERLY⏩⏩

Answer 1

Because the rod has been tied up from both ends thus the rod will be in static equilibrium.
Thus, we can apply both Fnet = 0 and Torque net = 0 here and get two equations to find out tensions in both strings.

Let's say the left string has tension T1 and the right string has tension T2.
Hence,
by applying Fnet = 0 in vertical direction

T1 + T2 = mg+mg = 2mg.......(1)

Now, applying Torque net equation and taking the left end of the rod as the origin
we get,
T2 * 1 m = mg*0.8 + mg * 0.5
Thus, T2 = 1.3 mg
And thus T1 = 0.7 mg.

Hence,
T1 : T2 = 0.7 mg : 1.3 mg = 7:13

The higher value of T2 can be even understood by a simple logic and feel that since the block has been placed nearer to the right end thus, more torque will be provided to the right string and hence to maintain the equilibrium, the magnitude of the tension in the right string will be obviously more.

Hence, the ratio of the tensions
T1 : T2 = 7:13

Hope this helps you !
#Dhruvsh