hey guys , plzzzz helppp meeeeeee...
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vaibhavpick466:
sorry I solved it but I am going to sleep
kkk no prblm
i know how its done
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1
cos(90-a) = sin a
sin(90-a) = cos a
now coming to the question
Lhs=
cos(90-A) /1+sin(90-A)
+ 1+sin(90-A) /cos(90-A)
= (sinA)/(1+cosA) + (1 +CosA)/SinA
= (sinA) ² +(1+cosA)²/(sinA) (1+cosA)
= 1 + sin²A+ cos²A+ 2cosA/ sinA + sinAcosA
= 2+2cosA / sin A + SinAcosA
= 2(1+cosA)/sinA(1+cosA)
= 2/ sinA
= 2cosecA
=.Rhs
hope you have got ur answer
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2
yeh book ka he que hai bas thoda ghumaya hua hai
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smj nahi aaya bhai hindi ya english m bolo
oo I was asking if u reside in gohpur Assam
nope m frm delhi..r u assame?
no I am Bengali
oo khub bhalo
hehe
hiii
u r Bengali anisha?
noo m from delhi
ok
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