Hey guys!!
Prove : H.C.F (ca,cb) = c * H.C.F(a,b).
{ where c belongs to Natural numbers (N)}
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Answered by
6
Hey
To prove :-
HCF ( ca , cb ) = c * HCF ( a , b ) .
Proof :-
Let's find HCF of a and b
a = a * 1
b = b * 1
So , HCF ( a , b ) = 1 .
Now ,
HCF of ca and cb .
ca = c * a
cb = c * b
So , HCF ( ca , cb ) = c
=> HCF ( ca , cb ) = c * 1
=> HCF ( ca , cb ) = c * HCF ( a , b )
thanks :)
Keep loving , keep smiling !!
To prove :-
HCF ( ca , cb ) = c * HCF ( a , b ) .
Proof :-
Let's find HCF of a and b
a = a * 1
b = b * 1
So , HCF ( a , b ) = 1 .
Now ,
HCF of ca and cb .
ca = c * a
cb = c * b
So , HCF ( ca , cb ) = c
=> HCF ( ca , cb ) = c * 1
=> HCF ( ca , cb ) = c * HCF ( a , b )
thanks :)
Keep loving , keep smiling !!
ria113:
thanks for ur solution .... ^-^
Answered by
11
Hello Genius,
Your solution is in the attachment.
Hope it helps you :))
Your solution is in the attachment.
Hope it helps you :))
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