Question

hey guys

solve it....​

Answer 1

Answer:

hlo sis

that's your answer

hope it helps you

Answer 2

r = 0.7cm

h = 2.4cm

l of cone = √(r²+h²) = √(0.49+5.76) = √6.25 = 2.5cm

Since the cylinder is hollowed out the TSA will be

= Base area of cylinder + LSA of cylinder +

LSA of cone

Base area of cylinder = πr² = 22/7 × 0.7 × 0.7

= 1.54cm²

LSA of cone = πrl = 22/7 × 0.7 × 2.5 = 5.5cm²

LSA of cylinder = 2πrh = 2 × 22/7 × 0.7 × 2.4

= 10.56cm²

Therefore the TSA of the remaining solid

= 1.54 + 5.5 + 10.56 = 17.6cm²

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