Question

hey guys

solve it.....​

Answer 1

Answer:

that's your answer

hope it helps you

Answer 2

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Step-by-step explanation:

CosA/1+sinA + 1+sinA/cosA=2secA

LHS..CosA(cosA) +(1+sinA)(1+sinA)/cosA(1+sinA)

cos^2A+1+sinA+sinA+sin^2A/cosA+CosAsinA

Cos^2A+sin^2A+1+2sinA/cosA+cosAsinA

2+2sinA/cosA+cosAsinA

2(1+sinA)/cosA(1+sinA)

[(1+sinA)/(1+sinA)] cancelled

2/cosA

2secA RHS... ( 1/cosA=secA)

.......LHS=RHS......

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