Hey guys
Solve it.... Fast...
Attachments:

Answers
Answered by
2
Given Set : A = { x : x is a factor of 12 }
As the Factors of 12 are : 1 , 2 , 3 , 4 , 6 , 12
⇒ Set : A = { 1 , 2 , 3 , 4 , 6 , 12 }
Given Set : B = { x : 3 ≤ x ≤ 7 where x ∈ N }
As Natural Numbers from 3 to 7 are 3 , 4 , 5 , 6 , 7
⇒ Set : B = { 3 , 4 , 5 , 6 , 7 }
A ∪ B = The Set which contains either the Elements of A or the Elements of B
⇒ A ∪ B = { 1 , 2 , 3 , 4 , 6 , 12 } ∪ { 3 , 4 , 5 , 6 , 7 }
⇒ A ∪ B = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 12 }
A ∩ B = The Set which contains the Elements which are common to Both A and B
⇒ A ∩ B = { 1 , 2 , 3 , 4 , 6 , 12 } ∩ { 3 , 4 , 5 , 6 , 7 }
The Elements both common to both A and B are 3 , 4 , 6
⇒ A ∩ B = { 3 , 4 , 6 }
Attachments:

prachi7742:
Awesome
Answered by
5
hey frnd....
heres your answer.
HOPE THIS HELPS YOU...☺☺☺
heres your answer.
HOPE THIS HELPS YOU...☺☺☺
Attachments:

Similar questions