Question

HEY GUYS SOLVE THIS PLZZZZ



Question 7

Answer 1

Solution:

$a + b + c ≠ 0 \\ \\ To\:\:prove\:\:\\\\ {a}^{3} + {b}^{3} + {c}^{3} = 3abc \\ \\ only \: \: when \: \: a = b = c$
formula:

${a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca) \\ \\ put \: a = b = c \\ \\ = (a + a + a)( {a}^{2} + {a}^{2} + {a}^{2} - {a}^{2} - {a}^{2} - {a}^{2} ) \\ \\ = 3a(0) \\ \\ {a}^{3} + {b}^{3} + {c}^{3} - 3abc = 0 \\ \\ {a}^{3} + {b}^{3} + {c}^{3} = 3abc$
hence proved.

Answer 2

In the attachment I have answered this problem .

The solution is simple and easy to understand.

See the attachment for detailed solution.