Question

hey guys
solve this question
a^2-b^2= 19
the value of a = ?
faster guys
..
A challenge for you. ​

Answer 1

Hey friend!!

Here is your answer..

${a}^{2} - {b}^{2} = 19\\ (a + b)(a - b) = 19 \\ \\ hence \: 19 \: is \: a \: prime \: no. \\ so \\ (a + b)(a - b) = 19 \times 1 \\ \\ a + b = 19 \\ a - b = 1 \\ \\ adding \: both \: the \: eq. \\ \\ 2a = 20 \\ \\ a = 10$

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