Question

hey! guys.. solve this question...

no spam.....​

Answer 1

Answer:

O2[AgF6]<O2<KO2.

Explanation:

O2[AsF6]  has O−2 ion while KO2 has O−2 ion .

E.C. of O2= KKσ22sσ∗22sσ22pzπ22pxπ22pyπ∗12pxπ∗12py |  Bond order 12(8−4)=2

E.C. of O+2= KKσ22sσ∗22sσ22pzπ22pxπ22pyπ∗12pxπ∗02py | Bond order =12(8−3)=2.5

E.C. of O−2= KKσ22sσ∗22sσ22pzπ22pxπ22pyπ∗22pxπ∗12py  | Bond order =12(8−5)=1.5

Higher the bond order, smaller is the bond length . So the order of O-O bond length is :

O2[AgF6]<O2<KO2.