Question

hey guys!!
solve this question with details.

Answer 1

$\huge\purple{As-Salamu-Alykum}$

__________

$\huge\orange{Given: }$

Moles of each Al and O2 = 0.36 mol

$\huge\blue{Required :}$

Amount of product formed = ?

$\huge\red{Solution:}$

Al + O2 --------> Al2O3

But this isn't balanced

So.....

$\huge\green{Balanced Equation :}$

4Al +3O2-----------> 2Al2O3

In question 0.36 moles are given

So.....

0.36/4Al +0.36/3O2 --------->0.36/2Al2O3

0.09Al + 0.18 O2 ------>0.18 Al2O3

$\huge\red{Amount of Al2O3 = 0.18mol}$

__________

$\huge\pink{INSHALLAH\;it\;will\;help\;U}$