Hey guys❤
Tell me about the relationship between the radius of curvature and focal length.
Answers
Answer:
f = R/2
Explanation:
✨Firstly Consider the attachment..
⭕A ray parallel to principal axis after reflection passes through the focus...
⚫Now a ray AB parallel to principal axis falling on a concave mirror at B. After reflection, the ray passes through the focus.
⚫The dotted line CB is the Normal at point B. Therefore, ∠ABC is the angle of incidence i and ∠FBC is the angle of reflection.
∠ABC = ∠FBC _______[law of reflection]
Also, ∠ABC = ∠FCB ______[Alt. int. angles]
therefore, ∠FBC = ∠FCB => FC = FB
⚫Now, if the aperture of the concave mirror is small, then the ray AB will be very close to the principal axis and point B will be very close to P.
Therefore, FB will be approximately equal to FP.
i.e., FC = FP
Now, FP + FC = R ......... [where R = radius of curvature]
therefore, FP + FP = R
=> 2FP = R
=> FP = R/2
=> f = R/2
↑↑↑↑↑↑↑↑↑↑____________PROVED
Before arriving at the answer let us first understand the meaning of these terms:-
⭕RADIUS OF CURVATURE:-
✍It is known to us that a spherical mirror has a pole and a point called the "centre of curvature ".
✍This distance between the pole and the centre of curvature is the RADIUS OF CURVATURE.
⭕FOCAL LENGTH:-
✍It is the length between the pole of a spherical mirror (optical centre of lens) and the focal point.
✍It is positive in case of a convex mirror and negative in that of a concave mirror.
▶️Let us now come at the relation between the focal length and centre of curvature.
⭕One important thing to be noted is that, in case of a plane mirror, the radius of curvature is taken as infinity.
⭕In case of lens ,if you are provided with refractive indices of the medium, you can have the lens maker formula.
where f is the focal length and r1 and r2 are the radius of curvature respectively. ✔✔