Physics, asked by choudhary21, 4 months ago

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The refractive index of the glass with respect to air is 1.5 The focus distance of a convex lens thus formed is 20 cm.

When it is immersed in a fluid with a refractive index of 1.33, what will be the focus distance of the lens.

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Answers

Answered by kajalagarwal10
0

Answer:

If refractive index of glass with respect to air is 1.5, then the refractive index of air with respect to glass will be:

(a) 3.00

(b) 1.50

(c) 0.75

(d) 0.67

Answer:

(d) 0.67

Explanation:

 aμg = 1.5

gμa = 1/aμg

= 1/1.5 = 0.666

= 0.67

Answered by Anonymous
1

Answer:

Refer to the attachment for solution

Explanation:

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