Question

HEY GUYS!



URGENT HELP SOLVE PLZ​

Answer 1

Answer:

Let nth minima of 400 nm wave coincides with mth minima of 560 nm wave.

Then,

(2n-1)(400/2) - (2m-1)(560/2)

2n-1 /2m-1 = 7/5 =14/10 ....

2n-1= 7

n= 4

2m-1=5

m=3

That is, 4th minima of 400 nm wave coincides with 3rd minima of 560 nm wave.

Location of this minima is-

y1 =[ (2×4-1).(1000).(400×10-6 ) ] / 2×0.1 (given,d=0.1 )

= 14 mm