Question

Hey Guys..... ❤️❤️

Verify the following...


$3(x - 1) \div 16 - 5(x - 4) \div 12 = 2(x - 6 \div 6 - 11 \div 24$
Where x=7

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Answer 1

Answer:No! The follwing  equation is not true for x = 7

Step-by-step explanation:

We have,

3(x - 1) ÷ 16 - 5(x - 4) ÷ 12 = 2( x - 6 ÷ 6)

Here,

LHS = 3(x - 1) ÷ 16 - 5(x - 4) ÷ 12

RHS = 2( x - 6 ÷ 6 - 11 ÷ 24)

Now,

LHS = 3(x - 1) ÷ 16 - 5(x - 4) ÷ 12

Putting x = 7 in LHS,

3(7 - 1) ÷ 16 - 5(7 - 4) ÷ 12

Solving brackets,

=3(6)÷16 - 5(3)÷12

Opening brackets

=18÷16 - 15÷12

Solving Division,

= 9/8 - 5/4

Changing 15/4 to 10/8,

=9/8 - 10/8

=(9 - 10)/8

LHS = -1/8

Similarly,

RHS =  2( x - 6 ÷ 6 - 11 ÷ 24)

Putting x = 7 in RHS,

= 2(7 - 6 ÷ 6 - 11 ÷ 24)

= 2( 7 - 1 - 11/24)

= 2( 6 - 11/24)

= 2(144 - 11)/24

= (144 - 11)/12

= 133/12

RHS = 133/12

∴ LHS ≠ RHS

Answer 2

Answer:

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