Question

Hey guys what would be the answer of it. Please write the steps to do it.

Answer 1

Given, p(x)=ax³-3(a-1)x-1.

Since 1 is the zero of the polynomial p(x)

Therefore by FACTOR THEOREM,
»p(1)=0
»a×(1)³-3(a-1)1-1=0
»a×1-3a+3-1=0
»a-3a+2=0
»-2a+2=0
»-2a=-2
»a=-2/-2
So, a=1

Hope this answer helps you mate.

Please mark me as the brainliest one.

Thank you.

Answer 2

Answer:

Step-by-step explanation:

for any xero say z it must satisfy

p(x) = 0

that means when we put zero of polynomial in place of x then the polynomial will be zero so let us do it

a(1)² -3 (1-1) x -1 = 0

a * 1 -3 (0) x -1 = 0

a - 0 * x -1 = 0

a - 1 = 0

a = 1

Hence the value of a is one