Math, asked by frenzyrocket, 8 months ago

Hey guys,
Whoever answers this question first and correctly in a simple manner will be marked BRAINLIEST!!!! Others will be five stared and thanked.
Here's the question:-
What must be added to the numbers 6, 10, 14, 22 so that they are in proportion?

Thanks

Answers

Answered by swati2406
4

Answer:

2

Step-by-step explanation:

Let the number ' x ' should be added

to the given numbers so that they

are in proportional.

Therefore ,

( 6 + x ) , ( 10 + x ) , ( 14 + x ) , ( 22 + x )

are in proportion .

Product of extrems = product of

means

( 6 + x ) ( 22 + x ) = ( 10 + x ) ( 14 + x )

132 + 28x + x² = 140 + 24x + x²

28x - 24x = 140 - 132

4x = 8

x = 8/2

x = 2

Therefore ,

Required number = x =2

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