Question

Hey guyz plz help me
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solve step by step....​

Answer 1

as y-2 = 0, y= 2 is one of the side

so two common y coordinate becomes 2

now put y= 2 in 2x - 3y +6 =0

2x - 6 +6 = 0

x= 0

Put y= 2 in 2x +3y -18= 0

2x +6 -18= 0

2x -12 = 0

x= 6

So (0,2) ( 6,2)


Now intersection of 2x - 3y +6 = 0

2x +3y -18= 0

subtract

-6y + 24 = 0

y = 4

2x -12 +6 = 0

2x -6 = 0

x= 3

so (3,4)


So
(0,2) ( 6,2) ( 3,4)


Area = 1/2 ( 6 ( 4 -2) + 3 ( 2 -2))

= 1/2 × 12 = 6