Question

Hey Guyz...plzz answer it fast...

A box of mass 10 kg rests on a horizontal floor.
A force "F" is applied on to the box as shown in the figure.
If the coefficient of friction between the floor and the box is 0.2.what minimum force "F" will make the block slide horizontally ???

A)4/ root 3 N
B)40/ root 3 N
C)20/ root 3 N
D)80N​

Answer 1

Answer:

20N

Explanation:

F = uMg = 0.2(10)*10 = 20N