Question

Hey guyz plzzz help


Find domain of the function.​

Answer 1

The answer is 0 . Value of x ,y,z is 1.

The domain of sin inverse function is [-1,1] and range is [-π/2,π/2] .

The maximum value of sin^-1 x ,sin^-1y and sin^-1z is π/2 . So for

sin^-1x + sin^-1y+ sin^-1z = 3π/2

sin^-1x=π/2

sin^-1y=π/2

sin^-1z=π/2 (maximum values)

Therefore x,y,z=1

Putting the values we get

1+1+1–9/3

=3–3

=0