Math, asked by zoyarose, 11 months ago

HEY GUYZZ ANSWER THE FIFTH QUESTION AS SOON AS POSSIBLE...THNKS

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Answered by satishrbilagi
2
ma/b + nb/b = mc/d + nd/d
m(a/b)+n=m(c/d)+n
m(a/b)=m(c/d)
a/b=c/d.
Answered by TheRevenant01
1

b(mc+nd) = d(ma+nb)

bmc + bnd = dma + dnb

bmc = dma

bc = da

a/b = c/d

Hence , a,b,c,d are in proportion

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Cheers!

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