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Please answer this..
The total number of electrons present in 4.6g of sodium is how much
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Answered by
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No. Of moles =given mass/molar mass
molar mass of Na is 23 so that we have n=4.6/23
=0.2
electrons = 0.2X na
=0.2X6.022*10^23
=1.29X10^23
thank you.
No. Of moles =given mass/molar mass
molar mass of Na is 23 so that we have n=4.6/23
=0.2
electrons = 0.2X na
=0.2X6.022*10^23
=1.29X10^23
thank you.
farahalrafeeq:
Thankyou.
Answered by
1
Molar Mass of Na = 23
No. Of moles =given mass/molar mass
=4.6/23=0.2moles
no. of atoms in 0. 2 moles =0. 2× 6.022×10^23
no. of electrons (e^-1= 11electrons) =0.2×6.022×10^23×11
=1.32506×10^25
Therefore, the total number of electrons present in 4.6g of sodium is 1.32506×10^25
No. Of moles =given mass/molar mass
=4.6/23=0.2moles
no. of atoms in 0. 2 moles =0. 2× 6.022×10^23
no. of electrons (e^-1= 11electrons) =0.2×6.022×10^23×11
=1.32506×10^25
Therefore, the total number of electrons present in 4.6g of sodium is 1.32506×10^25
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