Question

hey gyues........
solve this ​

Answer 1

From this figure:

BF = height of girl = 1.2 m,

AG = height of balloon from ground initially = 88.2 m,

AC = AG – GC

= 88.2 – 1.2

= 87 m

∠EBD = 30° and ∠ABC = 60°,

CD = ?

✔In Δ ABC;

${}{ \bf \tan(theta) = \frac{p}{b} }$

Where p is perpendicular and b is base.

tan(60°)

${}{{= \frac{87}{bc} }}$

√3=87/BC

BC= 87/√3

✔In ∆ ABC,

${}{ \bf{\tan(theta) = \frac{p}{b} }}$

tan(30°)=87/bd

1/√3=87/bd

BD=87√3 m.

✾Now the distance covered by the balloon will be,

CD=BD - BC

CD = 87√3 - 87/√3

CD= 174/√3

✾Now for rationalizing , multiply and divide by √3.

CD= 174/√3 ×√3/√3

CD=174/3×√3

✔◆CD= 58√3 m.

Answer 2

Answer:

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