hey......
help me in this question
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Answer:
LHS
= cosA/(1+sinA) +(1+sinA)/cosA
= {cos^2A +(1+sinA)^2}/cosA•(1+sinA)
= {cos^2A+1+sin^2A+2sinA}/cosA•(1+sinA
Since, sin²∅ +cos²∅ =1
= (1+1+2sinA)/cosA(1+sinA)
= 2(1+sinA)/cosA(1+sinA)
= 2/cosA
= 2 × 1/cosA
= 2 × secA
=> 2secA = RHS
√√√
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