Math, asked by meena52, 1 year ago

hey help me please.

stucked in these too help out please.
best explanation of all the too will may get brainliest
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Answers

Answered by siddhartharao77
2

A small correction in your question. The denominator should be cotA - cosecA + 1.

Given Equation is cotA + cosecA - 1/(cotA - cosecA + 1).

We know that cot^2A - cosec^2A = -1.

We know that (-) * (-) = +.

 = > \frac{(cotA + cosecA) + [cot^2A - cosec^2A]}{(cotA - cosecA + 1)}

We know that a^2 - b^2 = (a + b)(a - b).

 = > \frac{(cotA + cosecA) + [(cotA + cosecA)(cotA - cosecA)]}{cotA - cosecA + 1}

Take cotA + cosecA common, we get

 = > \frac{(cotA + cosecA)[1 + cotA - cosecA]}{cotA - cosecA + 1}

cotA - cosecA + 1 is in the numerator and denominator, so it will be cancelled.

= > cotA + cosecA

= > (cosA/sinA) + (1/sinA)

= > (1 + cosA)/sinA.


meena52: help me out
siddhartharao77: in the last 3rd step, i took 1 common from both.
siddhartharao77: sorry i took cotA + cosecA common. not 1 from last 3rd step!
meena52: i didn't get thatt
siddhartharao77: wait for 5 minutes..i will edit my answer!
meena52: ok
siddhartharao77: check my answer
meena52: thankyou so much
siddhartharao77: most welcome... Bye for now!
meena52: sure!!
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