Math, asked by Anonymous, 1 year ago

Hey!!! Here is your Maths question



(a + b - c)^{2}  - (a - b + c)^{2}
Using
(a + b)(a - b) =  {a}^{2}  -  {b}^{2}
formula

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Answers

Answered by Anonymous
3

Answer:

Step-by-step explanation:

❣Holla user❣

Here is ur ans⬇️⬇️

first Method :-

by (a+b+c)^2 formula

(a+b-c)^2=a^2+b^2-c^2+2ab-2bc-2ca

(a-b+c)^2=a^2-b^2+c^2-2ab-2bc+2ca

Now

(a+b-c)^2-(a-b+c)^2

a^2+b^2-c^2+2ab-2bc-2ca-[a^2-b^2+c^2-2ab-2bc+2ca]

a^2+b^2-c^2+2ab-2bc-2ca-a^2+b^2-c^2+2ab+2bc-2ca

2b^2-2c^2-4ac+4ab

2b^2+4ab-2c^2-4ac

2b(b+2a)-2c(c+2a)

(2b-2c)(b+2a)(c+2a)

Second Method:-

By (a^2-b^2) formulae

Referred the attachment below⬇️⬇️

Hope it helps u^_^

Attachments:

Anonymous: just see at the firat step
Anonymous: i had see all the step.
Anonymous: i had used( a+b+c)^2 formula
Anonymous: but i said to use (a+b)(a-b)=a^2-b^2
Anonymous: its not compulsory
Anonymous: in question they mentioned
Anonymous: wait let me solve these que in notebook.
Anonymous: thank you
Anonymous: thanks a lot
Anonymous: wello ❣
Answered by siddhartharao77
8

Answer:

4bc - 4ac

Step-by-step explanation:

Given Equation is (a + b - c)² - (a - b + c)²

∴ a² - b² = (a - b)(a + b)

⇒ (a + b - c - a + b - c)(a + b - c + a - b + c)

⇒ (2b - 2c)(2a)

⇒ 4bc - 4ac

Hope it helps!


siddhartharao77: Yes sis
Anonymous: bro we can use two method to solve these que.
Anonymous: one is (a+b+c)^2
Anonymous: ok listen , now the formula is (a+b)(a-b) = a^2-b^2 now , the question is (a+b-c)^2 - (a-b+c)^2 so the question is in the form of a^2-b^2. so we need to find (a+b)(a-b) ok so you did the process and got the answer as 4bc-4ca ok!!! now we got the values of a and b so it should be (a+b-c)^2-(a-b+c)^2=4bc-4ca as per the formula (a+b)(a-b). but it is not equal you can check it !!!
siddhartharao77: They are not the values of a and b.
Anonymous: then what
Anonymous: ok anyway i understood
Anonymous: thank you bro
Anonymous: thanks a lot
siddhartharao77: Welcome
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