Question

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Answer 1

Answer:

Let the point on x axis be (x,0)P

given distance from the point and (2,-5)A is equal to (-2,-9)b

So,

using distance formula ,

PA = PB

(x-2)^2 + (-5)^2 = (x-(-2))^2 + (-9)^2

x^2 + 4 - 4x + 25 = x^2 + 4 + 4x + 36

8x = -11

x = -11/8

so required point is (-11/8 , 0)

Answer 2

Answer:

hey

Step-by-step explanation: