Hey,I have a challenge for you all . Let's see that who will answer first . I will mark his/her as brainlist
Answers
Well,
if we see the three equations that have been given to us we can compare the powers of x in each term and by that we can say that,
x = y = z
Thus,
(1) is correct since for the value of x y and z as 3 each we would get the cube of 3 that is 27.
(2) is also correct since 12 as value for each x y and z we would get 12 cube that is 1728.
(4) is also correct since x + y + z = 12 and for value of 4 for each x y and z we can get this expression.
However the only incorrect option here is (3).
Since x + y + z = 3x = 3y = 3z = 32
Where ,
x = y = z = 32/3
however this is not possible since 32/3 is a fractional value and not a complete integer which contradicts the condition of the question.
Hence , (3) is incorrect.
Hope this helps you !
Answer:
One of the most simplest algebra and logic questions you'll get in mathematics.
Well,
if we see the three equations that have been given to us we can compare the powers of x in each term and by that we can say that,
x = y = z
Thus,
(1) is correct since for the value of x y and z as 3 each we would get the cube of 3 that is 27.
(2) is also correct since 12 as value for each x y and z we would get 12 cube that is 1728.
(4) is also correct since x + y + z = 12 and for value of 4 for each x y and z we can get this expression.
However the only incorrect option here is (3).
Since x + y + z = 3x = 3y = 3z = 32
Where ,
x = y = z = 32/3
however this is not possible since 32/3 is a fractional value and not a complete integer which contradicts the condition of the question.
Hence , (3) is incorrect.