Question

Hey! I have a question for you.
If sec 0 + tan 0 = p, then find the value of cosec 0.​

Answer 1

Answer:

cosec∅ = (p²+1)/(p²-1)

$\bold{\boxed{step\:by\:step\:explanation}}$

sec∅ + tan∅ = p ....(1)

as we know (sec²∅ - tan²∅= 1))

= (sec∅+tan∅)(sec∅ - tan∅ ) = 1

= p (sec∅ - tan∅ ) = 1

= (sec∅ - tan∅ ) = 1/p ...(2)

now we have 2 equation add them

we get

2sec∅ = (p²+1)/p

sec∅ = (p²+1)/2p. [cos∅ = 1/sec∅]

cos∅ = 2p/(p²+1)

now subtract both the above equations.

we get

2tan∅ = (p²-1)/p

tan∅ = (p²-1)/2p

we know

sin∅ = tan∅.cos∅

sin∅ = (p²-1)/2p x ( 2p/p²+1)

sin∅ = (p²-1)/(p²+1). [cosec∅ = 1/sin∅]

cosec∅ = (p²+1)/(p²-1)

$\bold{\boxed{hope\:this\:will\:help\:you}}$

Answer 2

Answer:

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