Question

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Answer 1

8)

$the \: sum \: of \: the \: angle \: of \: a \: triangle \: is \: 180 \\ \\ 3x + 4x + 5x = 180 \\ 12x = 180 \\ x = 15 \: \: \\ \\ 4x = 4 \times 15 = 60 \\ 3x = 3 \times 15 = 45 \\ 5x = 5 \times 15 = 75$

9)

$\: the \: sum \: of \: two \: corresponding \: angle \: = 180 \\ \\ (3x - 15) + (2x + 5) = 180 \\ 5x - 10 = 180 \\ 5x = 190 \\ x = 38 \: \\ \\ (3x - 15) = (3 \times 38 - 15) = 99 \\ (2 \times + 5) = (2 \times 38 + 5) = 81$

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Answer 2

Answer:

Step-by-step explanation:

8)              angle D = angle B =5x   (opp sides of llgm)

             in triangle ABD

4x+5x+3x=180      (angle sum property)

x=15 degree

then 5x=75 degree   ; 4x=60 degree    ;  3x=45 degree

then angle B = angle D= 75 degree

as we know , diagonals of llgm bisects the angles

so angle CAB = 60 degree and angle ACB = 45 degree

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