Question

hey! i m here with my second problem sum of maths help me​

Answer 1

Answer:

i don't know

sorry

so sorry

Answer 2

Step-by-step explanation:

In ∆PQA and ∆PRA,

PA=PA ..........................(Common)

<PQA=<PRA................(PQ and PR are perpendiculars from point P to sides AB and AC)

<QAP=<RAP................(AD is the bisector of <A)

Therefore,∆PQA=~∆PRA (AAS)

PQ=PR ..........(CPCT)