Question

hey ❣️







If sin A =3/5

calculate

(1) cos A

(2) tan A


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Answer 1

⏩Hey mate❤

Given here

SinA= 3/5

find here

(1) Cos A

(2) Tan A

Solution:-

Sin A=3/5

We know

Cos A= √[1-Sin²A]

= √[1-(3/5)²]

= √[1-9/25]

= √(16/25)

= 4/5

And,

Tan A= SinA/CosA

= (3/5) / (4/5)

= 3/5× 5/4

= 3/4

➡Hopes its help's u

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@Abhi❤❤

Answer 2

SOLUTION

$sin </u><u>A</u><u>= \frac{3}{5}</u><u>\</u><u>:</u><u>,</u><u> </u><u> </u><u>A</u><u> \: lies \: in \: first \: quadrant \\ </u><u>H</u><u>ence \\\ = >cos </u><u>A</u><u>= \sqrt{1 - {sin}^{2} </u><u>A</u><u>} \\ \\ = > \sqrt{1 - ( \frac{3}{5} ) {}^{2} } = > \sqrt{1 - \frac{9}{25} } \\ \\ = > \sqrt{ \frac{16}{25} } = > \frac{4}{5 } \\ \\ = > cos \: </u><u>A</u><u> = \frac{4}{5}$

tan A

$= > tan \:A = \frac{sinA}{cosA} \\ \\ = > \frac{ \frac{ \frac{3}{5} }{4} }{5} \\ \\ = > \frac{3}{5} \times \frac{5}{4} = > \frac{3}{4} \\ \\ = > tan \: A = \frac{3}{4}$

Hope it helps ☺️