hey! if the area of the rectangle is 460 sq mtrs.if length is 15% more than breadth, then what is the breadth ?
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4
hey!
here is your answer >>>
area ( Lenght * breadth) = 460
Let us take breadth as X ,
Then length will be , (15/100)x + x
=> (3x/20) + x
=> 23x/20 = length,
now,
(23x/20)(x) = 460
(23)x^2 = 460(20)
x^2 = (460*20)/23
x^2 = 20*20
x^2 = 400
x = √400
x = 20 meters!
Breadth is 20 meters,
length = (23*20)/20
=> 23 meters!
Hope my answer helps!✌️
here is your answer >>>
area ( Lenght * breadth) = 460
Let us take breadth as X ,
Then length will be , (15/100)x + x
=> (3x/20) + x
=> 23x/20 = length,
now,
(23x/20)(x) = 460
(23)x^2 = 460(20)
x^2 = (460*20)/23
x^2 = 20*20
x^2 = 400
x = √400
x = 20 meters!
Breadth is 20 meters,
length = (23*20)/20
=> 23 meters!
Hope my answer helps!✌️
Answered by
4
Hi there !!
Here's your answer
Given that ,
The length of the rectangle is 15% more than it's breadth
Let the breadth be x
Area of rectangle = length × Breadth
x² = 400
x = ✓400
x = 20
So,
the breadth is 20 metres
Here's your answer
Given that ,
The length of the rectangle is 15% more than it's breadth
Let the breadth be x
Area of rectangle = length × Breadth
x² = 400
x = ✓400
x = 20
So,
the breadth is 20 metres
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