Question

Hey!!

✔just solve it

✔No more useless answers.

✔Thanx

Answer 1

$\large{\mathbf{HELLO \: \: DEAR,}} \\ \\ \mathbf{WE \: \: KNOW \: \: THAT:-} \\ \\ \mathbf{Cot (A+B) = \frac{(CotA*CotB-1)}{(CotA + CotB )}}\\ \mathbf{Cot(45)=1} \\ \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \mathbf{now} \\ \\ \\ \mathbf{1=\frac{(CotA*CotB-1)}{(CotA + CotB )}}\\ \\ \mathbf{(CotA*CotB-1)=(CotA + CotB )} \\ \\ \mathbf{(CotA*CotB - cotA-cotB=1)} \\ \\ \mathbf{ADDING \: \: 1 \: \: TO \: \: BOTH \: \: SIDES.}\\ \\ \mathbf{we \: \: get,}\\ \\\mathbf{(cotA-1)(cotB - 1)=2}\\ \\ \\ \large{\mathbf{\underline{I \: \: HOPE \: \: ITS \: \: HELP \: \: YOU \: \: DEAR, \: \: THANKS}}}$

Answer 2

Heya!

Here is yr answer.....


Given,

A+B = 45°

=> (Cot A-1) (cot B-1)


cot(A+B) = cot A cot B - 1 / (cot A+ cot B)

cot(45) = Cot A cot B - 1 / (cot A + cot B)

1 = Cot A cot B - 1 / (cot A + cot B)

cot A + cot B = cot A cot B - 1

cot A cot B - cot A - cot B = 1

By adding one on both sides.....


(cot A-1) (cot B-1) = 2


Therefore,

(cot A -1) (cot B-1) = 2


Hope it hlpz..