Question

Hey Mate!

1. a. An iron ball requires 5000 J heat energy to raise its temperature by 10°C. Calculate the heat capacity of the iron ball.

b. If the mass of ball is 1.1 kg, find the specific heat capacity of iron.


⚔️ Spamming = 10 relevant answers reported ⚔️
​

Answer 1

QÛÊẞTÎÕÑ:

Q1·

a· An iron ball requires 5000 J heat energy to raise its temperature by 10°C. Calculate the heat capacity of the iron ball.

ÃÑẞWÊR:

SEE THE UPPER ATTACHMENT…!!!

Answer 2

Given ( a ) :-

• An Iron ball requires 5000 J heat energy to raise it temperature .

• It needs to raise it temperature by 10° C

Solution ( a) :-

Here,

We have to find heat capacity to Iron ball .

[ Heat capacity is the ratio of heat absorbed by the material to raise it's temperature. The heat capacity in calories per gram is called specific heat ]

As we know that,

Q = mc * ΔT

• Q stands for heat energy

• m stands for mass

• c specific heat capacity

• ΔT stands for change in temperature

But here, we have to find heat capacity

Therefore,

Q = Hc * ΔT

5000 = Hc * 10

Hc = 5000/10

Hc = 500 JK-1

Hence, Heat capacity is 500 JK-1

Given ( b)

• Here, Heat energy = 5000

• Change in Temperature = 10° C

• Mass of the ball = 1.1 Kg

Solution ( b)

Here,

We have to find specific heat

[ Specific heat is defined as the heat required to raise the temperature of the given substance by a given amount ]

Now ,

By using formula :-

Q = mc * ΔT

Here, Q = 5000 , m = 1.1 , ΔT = 10

Put the required values in the formula,

5000 = 1.1 * c * 10

5000 = 11 * c

c = 5000/11

c = 455 JK-1

Hence, The specific heat is 455JK-1 $.$