Hey mate answer my question
question no 15 (1)
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as we know diagonals of parallelogram bisect each other
so mid point of AC = mid point of BD
A( -2,1) , C(4,b) , B ( a,0), D (1,2)
( -2+4)/2, ( 1+b)/2 = a+1)/2, 0+2)/2
1, (1+b)/2 = a+1)/2, 1
compare
a+1)/2 = 1
a+1= 2
a= 1
1+b)/2 = 1
b= 1
so mid point of AC = mid point of BD
A( -2,1) , C(4,b) , B ( a,0), D (1,2)
( -2+4)/2, ( 1+b)/2 = a+1)/2, 0+2)/2
1, (1+b)/2 = a+1)/2, 1
compare
a+1)/2 = 1
a+1= 2
a= 1
1+b)/2 = 1
b= 1
Anshika788:
T8
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