Question

hey mate! can you prove this problem.

Answer 1

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$LHS=$

=$sec\: \theta+tan\: \theta$

=$(\frac{1}{cos\: \theta})+(\frac{sin\: \theta}{cos\: \theta})$

=$\frac{(1+sin\: \theta)}{cos\: \theta}$

Rationalise the Numerator

= $\frac{(1+sin\: \theta)}{cos\: \theta}× \frac{(1-sin\: \theta)}{(1-sin\: \theta)}$

= $\frac{1-sin^{2}\: \theta}{cos\: theta(1-sin\: \theta)}$

= $\frac{cos^{2}\: \theta}{cos\: theta(1-sin\: \theta)}$

= $\frac{cos\: \theta}{1-sin\: \theta}$

Answer 2

Answer:

Step-by-step explanation:

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