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CLASS 10 MATHS
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5√5xsq +20+10+8√5= 5x( √5x+4) 2√5( √5x+4)= (√5x+4)(5x+2√5)=0. Then x=-5/4 or 2√5/5
Anonymous:
actually I can see u where I had answer
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Here is your answer buddy:-
We will solve this question by MIDDLE TERM SPLITTING method.
Sum=+30.
Product= 5root5×8root5
= +200.
The required numbers are +20 & +10.
5root5x²+20x+10x+8root5=0
root5x(5x+4root5)+2(5x+4root5)=0
(root5x+2)(5x+4root5)=0
x=-2/root5 & -4root5/5
Hence, the zeroes are -2root5 and -4root5/5.
Hope it helps you.
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