hey mate here is my new question
A Person cannot see the object distinctly when placed beyond 2cm
now plzz solve the (b) part of the question plzzz of question 1
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Far point (Focal length) = 2 cm = + 0.02 m
Power = 1/Focal Length
Power = 1/0.02 D
Power = 50 D
Therefore, there is a need to put a convex lens of power 50 D
Power = 1/Focal Length
Power = 1/0.02 D
Power = 50 D
Therefore, there is a need to put a convex lens of power 50 D
himangi48bhatia:
but how to find focal length
The far point is itself the focal length.
ohk
thanx
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